77-82 Find the limit by interpreting the expression as an appropriate derivative. $e^{3x} - 1$ 77. $\lim_{x \to 0} \frac{e^{3x} - 1}{x}$ $10^h - 1$ 79. $\lim_{h \to 0} \frac{10^h - 1}{h}$ $9 \left[ \sin^{-1} \left( \frac{\sqrt{3}}{2} + \Delta x \right) \right]^2 - \pi^2$ 81. $\lim_{\Delta x \to 0} \frac{9 \left[ \sin^{-1} \left( \frac{\sqrt{3}}{2} + \Delta x \right) \right]^2 - \pi^2}{\Delta x}$ $3 \sec^{-1} w - \pi$ 82. $\lim_{w \to 2} \frac{3 \sec^{-1} w - \pi}{w - 2}$ $exp(x^2) - 1$ 78. $\lim_{x \to 0} \frac{exp(x^2) - 1}{x}$ $\tan^{-1}(1 + h) - \pi/4$ 80. $\lim_{h \to 0} \frac{\tan^{-1}(1 + h) - \pi/4}{h}$
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To find the limit of 3x-1 as x approaches 0, we can interpret this expression as the derivative of a function. Let's call the function f(x) = 3x-1. The derivative of f(x) is f'(x) = 3. Therefore, the limit as x approaches 0 of 3x-1 is equal to the derivative of Show more…
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In Exercises $82-83,$ use properties of limits and the following limits $$ \begin{array}{ll}{\lim _{x \rightarrow 0} \frac{\sin x}{x}=1,} & {\lim _{x \rightarrow 0} \frac{\cos x-1}{x}=0} \\ {\lim _{x \rightarrow 0} \sin x=0,} & {\lim _{x \rightarrow 0} \cos x=1}\end{array} $$ to find the indicated limit. $$ \lim _{x \rightarrow 0} \frac{\tan x}{x} $$
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Finding Limits Using Properties of Limits
In Exercises $82-83,$ use properties of limits and the following limits $$ \begin{array}{ll}{\lim _{x \rightarrow 0} \frac{\sin x}{x}=1,} & {\lim _{x \rightarrow 0} \frac{\cos x-1}{x}=0} \\ {\lim _{x \rightarrow 0} \sin x=0,} & {\lim _{x \rightarrow 0} \cos x=1}\end{array} $$ to find the indicated limit. $$ \lim _{x \rightarrow 0} \frac{2 \sin x+\cos x-1}{3 x} $$
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