00:01
In this question, we have been given a boundary value problem, which is del square u over del x square plus alpha e raised to minus x equals to del u over del t, where x is between 0 and pi, t is greater than 0.
00:20
Initial, the boundary condition is u t 0 equals to 0, and del u over del x at the point pi comma t is 0.
00:32
Then we have u of x comma 0 is f of x, and x is in between 0 and pi.
00:40
We need to find out the steady state solution.
00:44
So we will find the steady state solution.
00:49
So let's get started with that.
00:54
So first of all, we will let u x be steady state solution.
01:01
The steady state solution.
01:07
So what we will get from here.
01:09
So u double dash plus alpha e raised to minus x equals to 0.
01:14
This is from equation number one.
01:17
Ok, so that is what we have been given here.
01:21
So u double dash comes out to be minus alpha e raised to minus x.
01:26
So from this, what i will get from this, if we integrate it.
01:35
So this will be u dash is equals to integral of minus alpha e raised to minus x dx.
01:46
So this is by integration.
01:50
Ok, we have a equation, we are getting this.
01:54
This will be u dash equals to minus alpha.
01:58
And again, we will get minus will become plus e raised to minus x plus here i will get some constant...