Solve the differential equation by using the Wronskian determinant: $y'' - 2y' + y = \frac{e^t}{t^2 + 1}$
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The general solution will be the sum of the complementary solution ($y_c$) and a particular solution ($y_p$). First, let's find the complementary solution by solving the homogeneous equation: $y'' - 2y' + y = 0$ Show more…
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