Solve the differential equation. (Select all that apply.) y' = 3y^2 sin x y = 1 / (3 sin x + K) y = 1 / (3 cos x + K) y = - 1 / (3 sin x + K) y = 3 y = 0
Added by Kimberly R.
Close
Step 1
The general form of this type of equation is dy/dx = f(x, y), where f(x, y) is a function of x and y. In this case, f(x, y) = 3y^2 sin x. To solve this equation, we can use the method of separation of variables. This method involves rearranging the equation so Show more…
Show all steps
Your feedback will help us improve your experience
Avinash Vishwakarma and 78 other Calculus 1 / AB educators are ready to help you.
Ask a new question
Labs
Want to see this concept in action?
Explore this concept interactively to see how it behaves as you change inputs.
Key Concepts
Recommended Videos
Solve the differential equation. $$( y + \sin y ) y ^ { \prime } = x + x ^ { 3 }$$
Differential Equations
Separable Equations
Solution of the differential equation $\left[3 x y^{2}+x \sin (x y)\right] d y+\left[y^{3}+y \sin (x y)\right] d x=0$ is (A) $x y^{3}-\cos x y=c$ (B) $x y^{3}+\cos x y=c$ (C) $x y^{2}-\cos x y=c$ (D) $x y^{2}+\sin x y=c$
Recommended Textbooks
Calculus: Early Transcendentals
Thomas Calculus
Transcript
18,000,000+
Students on Numerade
Trusted by students at 8,000+ universities
Watch the video solution with this free unlock.
EMAIL
PASSWORD