Question

Solve the differential equation, subject to the given initial condition.\\ $\frac{dy}{dx} - 8xy - 16x = 0$; \quad $y(2) = 19$

          Solve the differential equation, subject to the given initial condition.\\
$\frac{dy}{dx} - 8xy - 16x = 0$; \quad $y(2) = 19$

Solve the differential equation, subject to the given initial condition.

(dy)/(dx) - 8xy - 16x = 0; y(2) = 19

Added by Amy C.

Calculus: Early Transcendentals

James Stewart 8th Edition

Instant Answer

Solved by Expert Pranil T

03/21/2022

Step 1

Step 1: Rearrange the differential equation to isolate dy/dx dy - 8xy - 16x = 0 dy = (8xy + 16x)dx Show more…

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Solve the differential equation, subject to the given initial condition. (dy)/(dx)-8xy-16x=0;,y(2)=19 Solve the differential eguation, subject to the given initial condition dy -8xy-16x=0; dx y(2)=19

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Solve the differential equation, subject to the given initial condition.\\ $\frac{dy}{dx} - 8xy - 16x = 0$; \quad $y(2) = 19$

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