Question

Solve the differential equation.\\ $x \frac{dy}{dx} = y + (x^2 - 3)^2$\ $\bigcirc y = \frac{1}{3}x^4 - 18x \ln x + cx$\ $\bigcirc y = \frac{1}{3}x^3 - 6x - \frac{9}{x} + c$\ $\bigcirc y = \frac{1}{3}x^4 - 6x^2 - 9 + cx$\ $\bigcirc y = x^4 - x^2 - 9 + cx$

          Solve the differential equation.\\
$x \frac{dy}{dx} = y + (x^2 - 3)^2$\
$\bigcirc y = \frac{1}{3}x^4 - 18x \ln x + cx$\
$\bigcirc y = \frac{1}{3}x^3 - 6x - \frac{9}{x} + c$\
$\bigcirc y = \frac{1}{3}x^4 - 6x^2 - 9 + cx$\
$\bigcirc y = x^4 - x^2 - 9 + cx$

Solve the differential equation.

x (dy)/(dx) = y + (x^2 - 3)^2◯ y = (1)/(3)x^4 - 18x ln x + cx◯ y = (1)/(3)x^3 - 6x - (9)/(x) + c◯ y = (1)/(3)x^4 - 6x^2 - 9 + cx◯ y = x^4 - x^2 - 9 + cx

Added by Tina P.

Calculus: Early Transcendentals

James Stewart 8th Edition

Instant Answer

Solved by Expert Adi S

07/23/2023

Step 1

Step 1: Rewrite the differential equation in the form dy/dx = f(x,y) Given: x(dy)/(dx) = y + (x^2 - 3)^2 Rewrite as: dy/dx = (y + (x^2 - 3)^2) / x Show more…

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Solve the differential equation. x(dy)/(dx)=y+(x^(2)-3)^(2) Solve the differential equation. x(dy)/(dx)=y+(x^(2)-3)^(2) y=(1)/(3)x^(4)-18xlnx+cx y=(1)/(3)x^(3)-6x-(9)/(x)+c y=(1)/(3)x^(4)-6x^(2)-9+cx y=x^(4)-x^(2)-9+cx Solve the differential equation =y+x2-32 X y= 9 +C S y=4-2-9+cx