Question

Solve the differential equation $y' = \frac{\sqrt{x}}{y}$. a. $4y^2 = 21x^{\frac{3}{2}} + C$ b. $7y^2 = 4x^{\frac{3}{2}} + C$ c. $4y^2 = 7x^{\frac{3}{2}} + C$ d. $21y^2 = 4x^{\frac{3}{2}} + C$ e. $21y^2 = 2x^{\frac{3}{2}} + C$

          Solve the differential equation $y' = \frac{\sqrt{x}}{y}$.
a. $4y^2 = 21x^{\frac{3}{2}} + C$
b. $7y^2 = 4x^{\frac{3}{2}} + C$
c. $4y^2 = 7x^{\frac{3}{2}} + C$
d. $21y^2 = 4x^{\frac{3}{2}} + C$
e. $21y^2 = 2x^{\frac{3}{2}} + C$

Solve the differential equation y' = (√(x))/(y).
a. 4y^2 = 21x^(3)/(2) + C
b. 7y^2 = 4x^(3)/(2) + C
c. 4y^2 = 7x^(3)/(2) + C
d. 21y^2 = 4x^(3)/(2) + C
e. 21y^2 = 2x^(3)/(2) + C

Added by Mario D.

Calculus: Early Transcendentals

James Stewart 8th Edition

Instant Answer

Solved by Expert Sri K

01/06/2023

Step 1

Step 1: Identify the given differential equation The given differential equation is y'(x) = (\sqrt(x))/(7y(x)). Show more…

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Solve the differential equation y^(')=(sqrt(x))/(7y). a. 4y^(2)=21x^((3)/(2))+C b. 7y^(2)=4x^((3)/(2))+C c. 4y^(2)=7x^((3)/(2))+C d. 21y^(2)=4x^((3)/(2))+C e. 21y^(2)=2x^((3)/(2))+C a. mi @b n+c mlN 0+ @a 21y4x +C Oe. 21y22x +C