Question

Solve the equation on the interval [0, 2?). cos 2x = \frac{\sqrt{2}}{2} \frac{\pi}{8}, \frac{7\pi}{8}, \frac{9\pi}{8}, \frac{15\pi}{8} \frac{\pi}{4}, \frac{3\pi}{4}, \frac{5\pi}{4}, \frac{7\pi}{4} 0, \frac{2\pi}{3}, \pi, \frac{4\pi}{3} no solution

          Solve the equation on the interval [0, 2?).
cos 2x = \frac{\sqrt{2}}{2}
\frac{\pi}{8}, \frac{7\pi}{8}, \frac{9\pi}{8}, \frac{15\pi}{8}
\frac{\pi}{4}, \frac{3\pi}{4}, \frac{5\pi}{4}, \frac{7\pi}{4}
0, \frac{2\pi}{3}, \pi, \frac{4\pi}{3}
no solution

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Solve the equation on the interval [0, 2?).
cos 2x = (√(2))/(2)
(π)/(8), (7π)/(8), (9π)/(8), (15π)/(8)
(π)/(4), (3π)/(4), (5π)/(4), (7π)/(4)
0, (2π)/(3), π, (4π)/(3)
no solution

Added by Sonia A.

Calculus: Early Transcendentals

James Stewart 8th Edition

Instant Answer

Solved by Expert Sanchit Jain

03/15/2023

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cos2x=1357 Show more…

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Solve the equation on the interval [0,2Ï€): cos(2x) = 1357 No solution

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