Question

Solve the equation on the interval $0 \le \theta < 2\pi$. $\tan \left(\frac{\theta}{2} + \frac{\pi}{4}\right) = -1$

          Solve the equation on the interval $0 \le \theta < 2\pi$.
$\tan \left(\frac{\theta}{2} + \frac{\pi}{4}\right) = -1$

Solve the equation on the interval 0 ≤θ < 2π.
tan((θ)/(2) + (π)/(4)) = -1

Added by James B.

Introductory and Intermediate Algebra for College Students 4th

Robert Blitzer 4th Edition

Instant Answer

Solved by Expert Ankit Gupta

08/04/2020

Step 1

The tangent identity states that tan(2x) = (2tan(x))/(1-tan^2(x)). So, the equation tan(2) = -1 can be rewritten as (2tan(1))/(1-tan^2(1)) = -1. Show more…

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Solve the equation on the interval 0<2 tan 2 -1 4

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Question

Solve the equation on the interval $0 \le \theta < 2\pi$. $\tan \left(\frac{\theta}{2} + \frac{\pi}{4}\right) = -1$

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