Question

Solve the following differential equation $-17\frac{d^2\phi}{dt^2} + 2\frac{d\phi}{dt} - 10\phi = 0$ Subject to the following boundary conditions $\phi(2\pi(\frac{-34}{26})) = -2, \phi(6) = 3$ Finally, evaluate your solution at t=4.5

          Solve the following differential equation
$-17\frac{d^2\phi}{dt^2} + 2\frac{d\phi}{dt} - 10\phi = 0$
Subject to the following boundary conditions
$\phi(2\pi(\frac{-34}{26})) = -2, \phi(6) = 3$
Finally, evaluate your solution at t=4.5

Solve the following differential equation
-17(d^2ϕ)/(dt^2) + 2(dϕ)/(dt) - 10ϕ = 0
Subject to the following boundary conditions
ϕ(2π((-34)/(26))) = -2, ϕ(6) = 3
Finally, evaluate your solution at t=4.5

Added by Jason C.

Calculus: Early Transcendentals

James Stewart 8th Edition

Instant Answer

Solved by Expert Sriram Soundarrajan

09/27/2020

Step 1

We can solve it by assuming a solution of the form $\phi(t) = e^{rt}$, where r is a constant. Show more…

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Solve the following differential equation $$-17\frac{d^2\phi}{dt^2} + 2\frac{d\phi}{dt} - 10\phi = 0$$ Subject to the following boundary conditions $$\phi(2\pi(\frac{-34}{26})) = -2, \phi(6) = 3$$ Finally, evaluate your solution at t=4.5