00:01
So, we have given the objective that is maximize of z is equal to that is z is equal to we have to write 26x plus 9y and now next we need to write that is 6x plus 8y is equal to 48 that is first subject to constraint.
00:21
13x plus y is equal to 48 and x is equal to according to this equation we need to write the coordinate of x and y intercept point those are when x is equal to 0 y is 6 and when y is equal to 0 x is 8.
00:40
Similarly, this given equation when x is equal to 0 y is 48 and when y is equal to 0 x is 3 .69 that is the value intercept points.
00:54
Now we need to draw the graph of these two functions.
00:58
Let's say this is our y axis and let's say this is our x axis from a given condition this is a y axis and this is x axis and here we need to put let's say this is a point 5 and here is 10.
01:18
Similarly, this is a point 5 and here is a 10.
01:21
So first intercept point we have here 0 and 8.
01:24
So let's say this is intercept point we have here 0, 6.
01:30
So let's draw the line.
01:34
So this is the line of our first equation 6, 0.
01:41
Now next we need to write here that is here is 10 and 48 approximate here.
01:48
Let's say this is our 40 point and this is a 48.
01:52
So from here we have to write it become 3 .69.
02:01
So from here it become that is let's say 48...