Solve the following inequality algebraically. |x-3|>=11 Solve the following inequality algebraically. $$|x - 3| \geq 11$$
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The inequality is of the form $|u| \geq a$, where $u = x - 3$ and $a = 11$. This type of inequality can be rewritten as two separate inequalities: $u \leq -a$ or $u \geq a$. Show more…
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