Solve the following initial value problem: y^3 - 5y'' - 22y' + 56y = 0, y(0) = 1, y'(0) = -2, y''(0) = -4.

Avinash V.

Question

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Solve the following initial value problem.\ y''' - 10y'' + 26y' = -40 e^{2x};\ y''(0) = 2, y'(0) = -3, y(0) = 2\ y(x) =