00:01
This problem wants us to solve the following system of equations.
00:04
And we're given negative 0 .8x plus 1 .3y equal to 0 .2, and 3 .2x minus 2 .5y equal to 4 .6.
00:11
And we're going to use elimination to solve this system.
00:14
And for elimination, it's always easier if we can multiply just one equation by one value instead of having to multiply both.
00:21
And to look at this equation, we can see that we can multiply negative 0 .8x to become 3 .2x if we multiply it by 4.
00:29
And it's already a negative, so we're going to get a negative result to 3 .2x, which is what we want because we want the x values to eliminate.
00:35
So the 4 will multiply by negative 0 .8x to give us negative 3 .2x.
00:40
But we also have to multiply 4 by 1 .3y and the 0 .2.
00:45
So 4 times 1 .3 gives us 5 .2y.
00:50
And then 4 times our 0 .2 gives us 0 .8.
00:53
And now we will eliminate our x values by adding our columns vertically...