In the following circuit find $v_c(t)$ and $i_L(t)$ given; $v_1(t) = 240 V$, $v_2(t) = 120 V$, $L = 1 H$, $C = \frac{1}{16} F$ and $R = 1.6 Ohm$.
Added by David M.
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Step 1
Given that v(t) = 240V and v(t) = 120V, we can find the initial conditions for the circuit. Since v(t) is the voltage across the capacitor, we can say that v_c(0) = 240V. Similarly, since v(t) is the voltage across the inductor, we can say that v_L(0) = 120V. Show more…
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