Question

3. [0/1 Points] DETAILS MY NOTES ZILLDIFFEQMODAP11 8.2.048. Solve the given initial-value problem. $X' = \begin{pmatrix} 8 & -1 \ 5 & 6 \end{pmatrix} X$, $X(0) = \begin{pmatrix} -4 \ 6 \end{pmatrix}$ $X(t) = \begin{pmatrix} -4e^{7t}\cos(2t) - 5e^{7t}\sin(2t) \ 6e^{7t}\cos(2t) - 13e^{7t}\sin(2t) \end{pmatrix}$

          3. [0/1 Points]
DETAILS
MY NOTES
ZILLDIFFEQMODAP11 8.2.048.
Solve the given initial-value problem.
$X' = \begin{pmatrix} 8 & -1 \ 5 & 6 \end{pmatrix} X$, $X(0) = \begin{pmatrix} -4 \ 6 \end{pmatrix}$
$X(t) = \begin{pmatrix} -4e^{7t}\cos(2t) - 5e^{7t}\sin(2t) \ 6e^{7t}\cos(2t) - 13e^{7t}\sin(2t) \end{pmatrix}$

Show more…

3. [0/1 Points]
DETAILS
MY NOTES
ZILLDIFFEQMODAP11 8.2.048.
Solve the given initial-value problem.
X' =
< p m a t r i x >
X, X(0) =
< p m a t r i x >
X(t) =
< p m a t r i x >

Added by Nicholas S.

Calculus: Early Transcendentals

James Stewart 8th Edition

Instant Answer

Solved by Expert Adi S

10/06/2022

Step 1

The matrix form of the system is x' = A*x, where A = [8, -1; 5, 6] and x = [x1; x2]. Show more…

Show all steps

lock

Thanks for your feedback!

Solve the given initial-value problem. x' = [8, -1; 5, 6]x, x(0) = [-4; 6] x(t) = -4e^(7t)cos(2t) - 5e^(7t)sin(2t), 6e^(7t)cos(2t) - 13e^(7t)sin(2t)

Play audio

Feedback

Powered by NumerAI

Adi S and 86 other subject Calculus 1 / AB educators are ready to help you.

Ask a new question

Labs

Want to see this concept in action?

NEW

Explore this concept interactively to see how it behaves as you change inputs.

View Labs

Key Concepts

Recommended Videos

Recommended Textbooks

Transcript

Ace is your personal tutor. It breaks down any question with clear steps so you can learn.

Start Using Ace

Continue solving this problem

Create a free account to:

View full step-by-step solution
Ask follow-up questions with Ace AI
Save progress and study later