Solve the initial value problem. ds/dt = 20t(5t^2 - 3)^3, s(1) = 2
Added by Cynthia D.
Step 1
Step 1:** Separate the variables in the differential equation: \[ds = 20t(5t^2 - 3)^3 dt\] ** Show more…
Show all steps
Close
Your feedback will help us improve your experience
Adi S and 57 other Calculus 1 / AB educators are ready to help you.
Ask a new question
Labs
Want to see this concept in action?
Explore this concept interactively to see how it behaves as you change inputs.
Key Concepts
Recommended Videos
Solve the initial value problem. $frac{ds}{dt} = 20t(5t^2 + 3)^8$, $s(1) = 2$
Suman K.
Solve the initial value problems. $$\frac{d s}{d t}=12 t\left(3 t^{2}-1\right)^{3}, \quad s(1)=3$$
Integrals
Indefinite Integrals and the Substitution Method
Solve the given initial-value problem. $$y^{\prime \prime}+4 y^{\prime}+3 y=\delta(t-2), \quad y(0)=1, \quad y^{\prime}(0)=-1$$
The Laplace Transform and Some Elementary Applications
Impulsive Driving Terms: The Dirac Delta Function
Recommended Textbooks
Calculus: Early Transcendentals
Thomas Calculus
Transcript
18,000,000+
Students on Numerade
Trusted by students at 8,000+ universities
Watch the video solution with this free unlock.
EMAIL
PASSWORD