Solve the initial value problem. $y'' + 0.4y' + 0.4y = 5.44e^{0.8x}$, $y(0) = 4.4$, $y'(0) = 2.52$ $y(x) = $
Added by Olivia R.
Close
Step 1
The general solution is given by the sum of the complementary solution ($y_c$) and the particular solution ($y_p$). The characteristic equation is $r^2 + 0.4r + 0.4 = 0$. Solving for $r$, we get $r = \frac{-0.4 \pm \sqrt{0.16 - 4(0.4)}}{2} = \frac{-0.4 \pm Show more…
Show all steps
Your feedback will help us improve your experience
Madhur L and 50 other Calculus 1 / AB educators are ready to help you.
Ask a new question
Labs
Want to see this concept in action?
Explore this concept interactively to see how it behaves as you change inputs.
Key Concepts
Recommended Videos
Solve the initial value problem dy - y = 8exp(x) + 5exp(6x) with x0 = 4
Madhur L.
Solve the following initial value problem. y'' - 10y' + 24y = 5x + e^(4x), y(0) = 0, y'(0) = 4 (not using Laplace)
Adi S.
Solve the following initial value problem. y''' - 10y'' + 34y' = -40 e^{4x}; y''(0) = 44, y'(0) = 2, y(0) = 8 y(x) =
Recommended Textbooks
Calculus: Early Transcendentals
Thomas Calculus
Transcript
Watch the video solution with this free unlock.
EMAIL
PASSWORD