Solve the initial value problem. $y'(t) = 1 + e^t$, $y(0) = 22$ The specific solution is $y(t) = t + e^t$.
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Step 1
First, let's rewrite the initial value problem as an equation: y(t) = 1 + e^(y0/2) Since we are given that the specific solution is y(t) = √2, we can substitute this into the equation: √2 = 1 + e^(y0/2) Show more…
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