Question

Solve the quadratic equation: \( 4(x+2)^{2}+21=33 \) \( x \approx 1.46 \) or \( x \approx-5.46 \) \( x \approx-0.27 \) or \( x \approx-3.73 \) \( x \approx-1.46 \) or \( x=5.46 \) \( x \approx 0.27 \) or \( x \approx 3.73 \)

          Solve the quadratic equation: \( 4(x+2)^{2}+21=33 \)
\( x \approx 1.46 \) or \( x \approx-5.46 \)
\( x \approx-0.27 \) or \( x \approx-3.73 \)
\( x \approx-1.46 \) or \( x=5.46 \)
\( x \approx 0.27 \) or \( x \approx 3.73 \)

Solve the quadratic equation: 4(x+2)^2+21=33
x ≈ 1.46 or x ≈-5.46
x ≈-0.27 or x ≈-3.73
x ≈-1.46 or x=5.46
x ≈ 0.27 or x ≈ 3.73

Added by Tyrone A.

Elementary and Intermediate Algebra

Alan S. Tussy, R. David Gustafson 5th Edition

Chapter 6

Instant Answer

Solved by Expert Piyush Kumar Gupta

Step 1

Step 1: Start with the given quadratic equation: \(4(x+2)^2 + 21 = 33\). Show more…

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Solve the quadratic equation: \( 4(x+2)^{2}+21=33 \) \( x \approx 1.46 \) or \( x \approx-5.46 \) \( x \approx-0.27 \) or \( x \approx-3.73 \) \( x \approx-1.46 \) or \( x=5.46 \) \( x \approx 0.27 \) or \( x \approx 3.73 \)