Question

Solve the right triangle. B = \boxed{}^\circ \boxed{}' (Round to the nearest integer as needed.) a = \boxed{} m (Round to the nearest integer as needed.) b = \boxed{} m (Round to the nearest integer as needed.)

          Solve the right triangle.
B = \boxed{}^\circ \boxed{}' (Round to the nearest integer as needed.)
a = \boxed{} m (Round to the nearest integer as needed.)
b = \boxed{} m (Round to the nearest integer as needed.)

Solve the right triangle.
B = ^∘' (Round to the nearest integer as needed.)
a = m (Round to the nearest integer as needed.)
b = m (Round to the nearest integer as needed.)

Added by Kelly D.

Introductory and Intermediate Algebra for College Students 4th

Robert Blitzer 4th Edition

Instant Answer

Solved by Expert Teresa Fuston

07/13/2022

Step 1

a^2 + b^2 = c^2 a^2 + 490.22^2 = 969^2 a^2 + 240220.0484 = 938961 a^2 = 698740.9516 a = √698740.9516 a ≈ 835.88 Show more…

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Solve the right triangle. B=, ' (Round to the nearest integer as needed.) a=m (Round to the nearest integer as needed.) b=m (Round to the nearest integer as needed.) Solve the right triangle B 969m 490.22 b A B= (Round to the nearest integer as needed.) m(Round to the nearest integer as needed.) m (Round to the nearest integer as needed.) a= b=