'Some fish have a density slightly less than that of water and must exert a force (swim) to stay submerged. What force must an 85.0-kg grouper exert to stay submerged in salt water if its body density is 1015 kg/m3?'
Added by Gregory C.
Step 1
Given that the body density of the grouper is 1015 kg/m^3 and its mass is 85.0 kg, we can use the formula: Density = mass/volume Rearranging the formula to solve for volume: Volume = mass/density Volume = 85.0 kg / 1015 kg/m^3 Volume = 0.0837 m^3 Show more…
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Suman K.
Some fish have a density slightly less than that of water and must exert a force (swim) to stay submerged. What force must an 85.0 -kg grouper exert to stay submerged in salt water if its body density is 1015 $\mathrm{kg} / \mathrm{m}^{3} ?$
Paul G.
Use g = 9.80 m / s2 and density of salt water = 1.025 x 103 kg / m3 A fish has a density slightly less than that of water and must exert a downward force to stay submerged. Calculate the magnitude of the force that an 85.0-kg fish must exert to stay submerged in salt water, if the density of its body is 1015 kg / m3.
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