00:01
And this question you asked to show that from the shortening equation, which is given by ih bar partial t, si t equals h, sii t.
00:15
When projected to a position basis, take the following form, si r t equals e minus i ee t over h bar, sii r.
00:26
Actually, this question is problematic.
00:28
It's not really true.
00:29
I mean, this is true only if a side r is an agon state of h.
00:34
If say r is not an against state of h, in general, you would need to sum over a new combination of these different states with different phase factors.
00:41
Okay.
00:42
So i assume that the classroom is actually implying that this one is an agent state of h.
00:51
Okay.
00:52
So if that's the case, then we project this equation onto the basis that we find ih, partial t, x, i'll say, arrow, right? use arrow, i use arrow, and then side t, and then h, arrow, right, and then side t, right? and then what we can do is to extend side t as eigenstates of h.
01:19
So again states, i would write them out...