State if the divergence test applies and if it does, either state that $\lim_{n \to \infty} a_n$ does not exist or find $\lim_{n \to \infty} a_n$: $\lim_{n \to \infty} a_n = \frac{n}{\sqrt{3n^2 + 2n + 1}}$
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The divergence (nth-term) test for a series Σ a_n requires computing lim_{n->∞} a_n; if this limit is nonzero or does not exist, the series diverges. We will compute the limit. Show more…
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