State the value of the length field in SHA-512 if the length of the message is: 1) 1919 bits 2) 1920 bits 3) 194 bits
Added by Guillermo D.
Step 1
So, we need to find the smallest multiple of 1024 (since SHA-512 has a block size of 1024 bits) that is greater than or equal to 1919 + 1 + 128 (the message length, the '1' bit, and the 128-bit length field). 1919 + 1 + 128 = 2048 The smallest multiple of 1024 Show more…
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