Question

Strontium–90 (90Sr) is a by–product of nuclear fission with a half–life of approximately 28.9 yr. After the Chernobyl nuclear reactor accident in 1986, large areas surrounding the site were contaminated with 90Sr. If 5 ?g (micrograms) of 90Sr is present in a sample, the function A(t) = 5(1/2)^(t/28.9) gives the amount A(t) (in ?g) present after t years. Evaluate the function for the given values of t and interpret the meaning in context. Round to 3 decimal places if necessary. Part 1 a. A(144.5) = 0.625 Part 2 b. A(86.7) =

          Strontium–90 (90Sr) is a by–product of nuclear fission with a half–life of approximately 28.9 yr. After the Chernobyl nuclear reactor accident in 1986, large areas surrounding the site were contaminated with 90Sr. If 5 ?g (micrograms) of 90Sr is present in a sample, the function A(t) = 5(1/2)^(t/28.9) gives the amount A(t) (in ?g) present after t years. Evaluate the function for the given values of t and interpret the meaning in context. Round to 3 decimal places if necessary.

Part 1
a. A(144.5) = 0.625

Part 2
b. A(86.7) =

Strontium–90 (90Sr) is a by–product of nuclear fission with a half–life of approximately 28.9 yr. After the Chernobyl nuclear reactor accident in 1986, large areas surrounding the site were contaminated with 90Sr. If 5 ?g (micrograms) of 90Sr is present in a sample, the function A(t) = 5(1/2)^(t/28.9) gives the amount A(t) (in ?g) present after t years. Evaluate the function for the given values of t and interpret the meaning in context. Round to 3 decimal places if necessary.

Part 1
a. A(144.5) = 0.625

Part 2
b. A(86.7) =

Added by Hunter R.

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