Question

$\sum_{n=1}^{\infty} \int_{1 / n^4}^{2 / n^4} 4 n^5 e^{-n^5 x} d x$ is equal to A) $\frac{3 e}{e^2-1}$ B) $\frac{2 e}{e^2-1}$ C) $\frac{e}{e^2-1}$ D) $\frac{4 t}{e^2-1}$ E) $\frac{e}{e-1}$

Name: sumn1infty int1 n42 n4 4 n5 e n5 x d x is equal to a frac3 ee2 1 b frac2 ee2 1 c fracee2 1 d frac4 te2 1 e fracee 1
Uploaded: 2023-06-12T13:37:04-08:00
Duration: 1 min 48 s
Channel: Bcrypt_Sha256$$2B$12$We1Wwocamog01O5I.V2Tkouxdh4Ofnmgpwkor7Leaonfpu0Ubfpua Bcrypt_Sha256$$2B$12$We1Wwocamog01O5I.V2Tkokttmmj7Lscvwvlptp4Rlhbswcdg9.Wy
Description: sumn1infty int1 n42 n4 4 n5 e n5 x d x is equal to a frac3 ee2 1 b frac2 ee2 1 c fracee2 1 d frac4 te2 1 e fracee 1

          $\sum_{n=1}^{\infty} \int_{1 / n^4}^{2 / n^4} 4 n^5 e^{-n^5 x} d x$ is equal to
A) $\frac{3 e}{e^2-1}$
B) $\frac{2 e}{e^2-1}$
C) $\frac{e}{e^2-1}$
D) $\frac{4 t}{e^2-1}$
E) $\frac{e}{e-1}$

Added by Atamert E.

Mathematical Methods in the Physical Sciences

Mary L. Boas 2nd Edition

Chapter 1

Instant Answer

Solved by Expert Bcrypt_Sha256$$2B$12$We1Wwocamog01O5I.V2Tkouxdh4Ofnmgpwkor7Leaonfpu0Ubfpua Bcrypt_Sha256$$2B$12$We1Wwocamog01O5I.V2Tkokttmmj7Lscvwvlptp4Rlhbswcdg9.Wy

06/12/2023

Step 1

Now we have the sum: $\sum_{n=1}^{\infty} (e^{-n} - e^{-2n})$. This is a sum of two geometric series. Show more…

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$\sum_{n=1}^{\infty} \int_{1 / n^4}^{2 / n^4} 4 n^5 e^{-n^5 x} d x$ is equal to A) $\frac{3 e}{e^2-1}$ B) $\frac{2 e}{e^2-1}$ C) $\frac{e}{e^2-1}$ D) $\frac{4 t}{e^2-1}$ E) $\frac{e}{e-1}$

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