00:01
In this problem we have the following charge configuration.
00:07
We have q2 here, q3 here, q1 here.
00:18
Let's say this is a, this is b.
00:22
We have q1 equal to minus 12, 10 to the power minus 13 quoloms.
00:30
Q2 equal to 5 nanopulombs, so 10 to the power minus 9.
00:35
Q3 is 8 .9, 10 to the power minus 14 culloms.
00:45
And we have this distance a equal to 250 centimeters and b equal to 300 centimeters or 2 .5 meters and 3 meters and 3 meters.
01:05
Let's also remember the culum constant k equal to 8 .99 10 to the power 9 newton meter square per column square.
01:16
Okay, now with this setup we are going to find the net force on this charge q2.
01:24
Okay, let us assume this coordinate system such that q2 is at the origin.
01:35
And with that, let us write down the position vectors of all these.
01:41
Particles.
01:43
For r1, namely the position of q1, we have the x coordinate equal to a and the y coordinate equal to b.
01:53
For r2, we have the origin and for the third one, we have x equal to a, y equal to zero.
02:05
Okay, now let us write down the force on the second particle using superposition.
02:12
So we have force on the second one due to the first one plus force on the second one due to the third one...