Question

Suppose a 250. mL flask is filled with 1.4 mol of $NO_3$ and 0.60 mol of $NO_2$. The following reaction becomes possible: $NO_3(g) + NO(g) \rightleftharpoons 2NO_2(g)$ The equilibrium constant $K$ for this reaction is 6.83 at the temperature of the flask. Calculate the equilibrium molarity of $NO_2$. Round your answer to two decimal places.

Name: suppose a 250 ml flask is filled with 14 mol of no3 and 060 mol of no2 the following reaction becomes possible no3g nog rightleftharpoons 2no2g the equilibrium constant k for this reacti 66632
Uploaded: 2024-03-01T21:29:17-08:00
Duration: 3 min 11 s
Channel: David Collins
Description: suppose a 250 ml flask is filled with 14 mol of no3 and 060 mol of no2 the following reaction becomes possible no3g nog rightleftharpoons 2no2g the equilibrium constant k for this reacti 66632

          Suppose a 250. mL flask is filled with 1.4 mol of $NO_3$ and 0.60 mol of $NO_2$. The following reaction becomes possible:
$NO_3(g) + NO(g) \rightleftharpoons 2NO_2(g)$
The equilibrium constant $K$ for this reaction is 6.83 at the temperature of the flask.
Calculate the equilibrium molarity of $NO_2$. Round your answer to two decimal places.

suppose a 250 ml flask is filled with 14 mol of no3 and 060 mol of no2 the following reaction becomes possible no3g nog rightleftharpoons 2no2g the equilibrium constant k for this reacti 66632

Added by James L.

Chemistry: Structure and Properties

Nivaldo Tro 2nd Edition

Instant Answer

Solved by Expert David Collins

03/01/2024

Step 1

The volume of the flask is 250 mL, which is 0.250 L. $[NO_3]_0 = \frac{1.4 \text{ mol}}{0.250 \text{ L}} = 5.6 \text{ M}$ $[NO_2]_0 = \frac{0.60 \text{ mol}}{0.250 \text{ L}} = 2.4 \text{ M}$ $[NO]_0 = 0 \text{ M}$ (Since NO is not mentioned in the initial Show more…

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Suppose a 250. mL flask is filled with 1.4 mol of $NO_3$ and 0.60 mol of $NO_2$. The following reaction becomes possible: $NO_3(g) + NO(g) \rightleftharpoons 2NO_2(g)$ The equilibrium constant $K$ for this reaction is 6.83 at the temperature of the flask. Calculate the equilibrium molarity of $NO_2$. Round your answer to two decimal places.