Question

Q1 1 Point Suppose a discrete random variable $X$ has the pmf $p_X(k) = \begin{cases} \frac{1}{5} & k = -2, -1, 0, 1, 2, \\ 0 & \text{otherwise.} \end{cases}$ Calculate $E[|X|]$. 0 1/5 1/2 4/5 1 6/5 3/2 Save Answer

          Q1
1 Point
Suppose a discrete random variable $X$ has the pmf
$p_X(k) = \begin{cases} \frac{1}{5} & k = -2, -1, 0, 1, 2, \\ 0 & \text{otherwise.} \end{cases}$
Calculate $E[|X|]$.
0
1/5
1/2
4/5
1
6/5
3/2
Save Answer

Q1
1 Point
Suppose a discrete random variable X has the pmf
pX(k) = (1)/(5) k = -2, -1, 0, 1, 2,
0 otherwise.
Calculate E[|X|].
0
1/5
1/2
4/5
1
6/5
3/2
Save Answer

Added by William M.

Elementary Statistics a Step by Step Approach

Allan G. Bluman 9th Edition

Instant Answer

Solved by Expert David Nguyen

04/25/2022

Step 1

The pmf of X is given as: P(X = -2) = 1/5 P(X = -1) = 1/5 P(X = 0) = 1/5 P(X = 1) = 1/5 P(X = 2) = 1/5 P(X = k) = 0 for all other values of k. Show more…

Show all steps

Thanks for your feedback!

Suppose a discrete random variable XX has the pmfpX(k)={1/5. k=−2,−1,0,1,2, {0 otherwise. Calculate E[∣X∣]. Q1 1 Point Suppose a discrete random variable X has the pmf k=-2,-1,0,1,2, otherwise. Px(k) Calculate E [|X|]. O 0 O 1/5 O 1/2 O 4/5 O 1 O 6/5 O 3/2 Save Answer