00:01
All right, so we're going to suppose that n is 6 and the sample correlation coefficient r is 0 .896.
00:07
And we're going to test if r is significant at the alpha of 0 .01 level of significance, which means it's going to be...
00:14
And we're using a two -tailed test, so a null is that rho is equal to 0.
00:21
And the alternative...
00:24
Let me draw it better.
00:25
The alternative, the two -tailed alternative is that rho is not equal to 0.
00:30
We're testing this level of significance.
00:31
And we're going to use a critical value approach, which means if the absolute value of our test statistic is greater than our t critical value, and the t critical value is based on the 0 .01 over 2 value with the degrees of freedom, which is found by taking n minus 1, that's going to...
00:49
We're going to reject our null hypothesis.
00:51
This is our rejection rule.
00:53
This is our rejection rule.
01:01
Okay.
01:01
So, the way we're going to get our t statistic is by taking the correlation coefficient...
01:05
Or the sample correlation coefficient r times n minus 2 divided by the square root of 1 minus r squared, which is literally...
01:15
I know it's capital r, but it's really the...
01:17
It's r value squared.
01:19
So let's go ahead and get those.
01:21
So the critical value is 4 .604.
01:26
I got it using this t, i, and v function.
01:27
You put in your alpha and then your degrees of freedom because if n is 6...
01:31
Oops, i wrote that wrong.
01:32
This should be n minus 2.
01:34
Sorry about that.
01:34
N minus 2 degrees of freedom.
01:36
So 6 minus 2 is 4...