Question

Suppose $f: A \to B$ is a function and $X \subseteq A$. Check all the statements that are true: A. $f^{-1}(f(X)) \subseteq X$ B. $f^{-1}(f(X)) \subseteq X$ if $f$ is 1-1 C. $f^{-1}(f(X)) \supseteq X$ D. $f^{-1}(f(X)) \supseteq X$ if $f$ is 1-1 E. None of the above

          Suppose $f: A \to B$ is a function and $X \subseteq A$. Check all the statements that are true:
A. $f^{-1}(f(X)) \subseteq X$
B. $f^{-1}(f(X)) \subseteq X$ if $f$ is 1-1
C. $f^{-1}(f(X)) \supseteq X$
D. $f^{-1}(f(X)) \supseteq X$ if $f$ is 1-1
E. None of the above
        
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Suppose f: A → B is a function and X ⊆ A. Check all the statements that are true:
A. f^-1(f(X)) ⊆ X
B. f^-1(f(X)) ⊆ X if f is 1-1
C. f^-1(f(X)) ⊇ X
D. f^-1(f(X)) ⊇ X if f is 1-1
E. None of the above

Added by Amparo R.

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Calculus: Early Transcendentals
Calculus: Early Transcendentals
James Stewart 8th Edition
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Suppose f: A -> B is a function and x ∈ A. Check all the statements that are true: A. f^(-1)(f(x)) ∈ x B. f^(-1)(f(x)) ∈ x if f is 1-1 C. f^(-1)(f(x)) ⊇ x D. f^(-1)(f(x)) ⊇ x if f is 1-1 E. None of the above Suppose f: A -> B is a function and X ⊂ A. Check all the statements that are true: A. f^(-1)(f(X)) ⊂ X B. f^(-1)f(X) ⊂ X if f is 1-1 C. f^(-1)f(XX) D. f^(-1)fXX if f is 1-1 E. None of the above
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Transcript

-
00:01 Hello everyone, let's solve the given question.
00:02 So, according to the question in the part 1st, 1, 2, 1 and on 2, it is because the each element have different images and range is equal to co -domain.
00:31 Now, moving to part 2nd, then it is neither 1, 1 nor on 2, it is because a and c have same image, b and range is not equal to co -domain...
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