Suppose f is an even function and $int_{-7}^{7} f(x) dx = 6$. a. Evaluate $int_{0}^{7} f(x) dx$ b. Evaluate $int_{-7}^{7} xf(x) dx$ a. Evaluate the definite integral. $int_{0}^{7} f(x) dx = square$ (Simplify your answer.) b. Evaluate the definite integral. $int_{-7}^{7} xf(x) dx = square$ (Simplify your answer.)
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Since \(f\) is even, we know that \(\int_{-a}^{a} f(x) dx = 2 \int_{0}^{a} f(x) dx\). Therefore, \(\int_{0}^{7} f(x) dx = 2 \times 6 = 12\). ** Show more…
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