Question

Suppose f'' is continuous on (-∞, ∞). (a) If f'(-1) = 0 and f''(-1) = -1, what can you say about f? At x = -1, f has a local maximum. At x = -1, f has a local minimum. At x = -1, f does not have a maximum or minimum. There is not enough information. (b) If f'(2) = 0 and f''(2) = 0, what can you say about f? At x = 2, f has a local maximum. At x = 2, f has a local minimum. At x = 2, f does not have a maximum or minimum. There is not enough information.

Name: suppose f is continuous on a if f 1 0 and f 1 1 what can you say about f at x 1 f has local maximumat x 1 f has a local minimum at x 1 f has not a maximum or minimumthere is not enough infor 30671
Uploaded: 2022-10-11T14:09:09-08:00
Duration: 3 min 59 s
Channel: Adi S
Description: suppose f is continuous on a if f 1 0 and f 1 1 what can you say about f at x 1 f has local maximumat x 1 f has a local minimum at x 1 f has not a maximum or minimumthere is not enough infor 30671

          Suppose f'' is continuous on (-∞, ∞).
(a) If f'(-1) = 0 and f''(-1) = -1, what can you say about f?
At x = -1, f has a local maximum. At x = -1, f has a local minimum. At x = -1, f does not have a maximum or minimum. There is not enough information.
(b) If f'(2) = 0 and f''(2) = 0, what can you say about f?
At x = 2, f has a local maximum. At x = 2, f has a local minimum. At x = 2, f does not have a maximum or minimum. There is not enough information.

Added by -Ngeles W.

Calculus: Early Transcendentals

James Stewart 8th Edition

Instant Answer

Solved by Expert Adi S

10/11/2022

Step 1

Step 1: For the first part of the question, we are given that f'(-1) = 0 and f''(-1) = -1. Show more…

Show all steps

Thanks for your feedback!

Suppose f'' is continuous on (-∞, ∞). (a) If f'(-1) = 0 and f''(-1) = -1, what can you say about f? At x = -1, f has a local maximum. At x = -1, f has a local minimum. At x = -1, f does not have a maximum or minimum. There is not enough information. (b) If f'(2) = 0 and f''(2) = 0, what can you say about f? At x = 2, f has a local maximum. At x = 2, f has a local minimum. At x = 2, f does not have a maximum or minimum. There is not enough information.