00:01
We are starting with a population that has a mean mu of 70 and a standard deviation sigma of 44.
00:07
But we aren't looking at individual observations, we are looking at a sample of size 64.
00:13
So part a we want to describe this distribution.
00:17
Now i don't know the shape of the original population distribution, but i do know if i take every possible sample of size 64, take the means and plot them out, i get something approximately normal.
00:30
This is because of the central limit theorem, which states that as sample size increases, sample means become more and more normally distributed.
00:39
If n is at least 30, you can treat them as approximately normal.
00:43
The mean of the means is the same as the population mean.
00:47
The standard deviation of the sample means, or standard error, is sigma over root n.
00:53
So if i want to describe this distribution, it is approximately normal.
01:00
It has a mean of 70, a standard deviation 44 over root 64 is 5 .5.
01:10
Part b, what value corresponds to a sample mean of 75 .5? so we're looking for the corresponding z -score.
01:20
This tells you how many standard deviations away from the mean a value is.
01:24
It's the standardized score.
01:26
You get it by taking the value, here a sample mean, subtracting the mean of its distribution, dividing by the standard deviation of its distribution.
01:34
Here that is 1.
01:38
It is one standard error above the mean.
01:45
So what we're saying is that 75 .5 on this sampling distribution corresponds to a value of 1 on the standard normal curve.
01:55
Now we want the probability that the sample mean would be less than this value.
02:01
Okay, so to find this you need something with the normal distribution built in.
02:06
The functions have to integrate.
02:07
To do this by hand is just too complicated...