Suppose that a fourth order differential equation has a solution $y = 6e^{2x} \cos(x)$.
(a) Find such a differential equation, assuming it is homogeneous and has constant coefficients.
$y'''' - 8y''' + 24y'' - 32y' + 16y = 0$
Enter the derivatives as $y, y', y'', \dots$. Don't forget the equal sign.
(b) Find the general solution to this differential equation.
$(c_1 + c_2x + c_3x^2 + c_4x^3)e^{2x}$
In your answer, use $c_1, c_2, c_3$ and $c_4$ to denote arbitrary constants and $x$ the independent variable. Enter $c_1$ as c1, $c_2$ as c2, etc.