Question

Suppose that $f$ is a function given as $f(x) = -5x + 7$. We will compute the derivative of $f$ at $x = 3$ as follows. First, we will compute and simplify the expression $f(3 + h)$. $f(3 + h) = $ Then we compute and simplify the difference quotient between $x = 3$ and $x = 3 + h$. $frac{f(3 + h) - f(3)}{h} = $ The derivative of the function at $x = 3$ is the limit of the difference quotient as $h$ approaches zero. $f'(3) = lim_{h o 0} frac{f(3 + h) - f(3)}{h} = $

          Suppose that $f$ is a function given as $f(x) = -5x + 7$. We will compute the derivative of $f$ at $x = 3$ as follows.

First, we will compute and simplify the expression $f(3 + h)$.
$f(3 + h) = $

Then we compute and simplify the difference quotient between $x = 3$ and $x = 3 + h$.
$frac{f(3 + h) - f(3)}{h} = $

The derivative of the function at $x = 3$ is the limit of the difference quotient as $h$ approaches zero.
$f'(3) = lim_{h 	o 0} frac{f(3 + h) - f(3)}{h} = $

$Suppose that f is a function given as f(x) = -5x + 7. We will compute the derivative of f at x = 3 as follows. First, we will compute and simplify the expression f(3 + h). f(3 + h) = Then we compute and simplify the difference quotient between x = 3 and x = 3 + h. fracf(3 + h) - f(3)h = The derivative of the function at x = 3 is the limit of the difference quotient as h approaches zero. f'(3) = limh o 0 fracf(3 + h) - f(3)h =$

Added by Albert M.

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