Question

Suppose that $f$ is a function given as $f(x) = \frac{1}{3x - 1}$. Simplify the expression $f(x + h)$. $f(x + h) = $ Simplify the difference quotient, $\frac{f(x + h) - f(x)}{h}$. $\frac{f(x + h) - f(x)}{h} = $ The derivative of the function at $x$ is the limit of the difference quotient as $h$ approaches zero. $f'(x) = \lim_{h \to 0} \frac{f(x + h) - f(x)}{h} = $

          Suppose that $f$ is a function given as $f(x) = \frac{1}{3x - 1}$.
Simplify the expression $f(x + h)$.
$f(x + h) = $
Simplify the difference quotient, $\frac{f(x + h) - f(x)}{h}$.
$\frac{f(x + h) - f(x)}{h} = $
The derivative of the function at $x$ is the limit of the difference quotient as $h$ approaches zero.
$f'(x) = \lim_{h \to 0} \frac{f(x + h) - f(x)}{h} = $

Suppose that f is a function given as f(x) = (1)/(3x - 1).
Simplify the expression f(x + h).
f(x + h) =
Simplify the difference quotient, (f(x + h) - f(x))/(h).
(f(x + h) - f(x))/(h) =
The derivative of the function at x is the limit of the difference quotient as h approaches zero.
f'(x) = limh → 0(f(x + h) - f(x))/(h) =

Added by Cynthia P.

Calculus: Early Transcendentals

James Stewart 8th Edition

Instant Answer

Solved by Expert Ankit Gupta

07/07/2020

Step 1

Step 1: To find $f(x+h)$, we substitute $x+h$ for $x$ in the expression for $f(x)$. Show more…

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Suppose that $f$ is a function given as $f(x) = \frac{1}{3x-1}$. Simplify the expression $f(x + h)$. $f(x+h) = $ Simplify the difference quotient, $\frac{f(x+h) - f(x)}{h}$. $\frac{f(x+h) - f(x)}{h} = $ The derivative of the function at $x$ is the limit of the difference quotient as $h$ approaches zero. $f'(x) = \lim_{h \to 0} \frac{f(x+h) - f(x)}{h} = $