00:02
Okay, so we have the function 2x square root of 2x squared plus 3.
00:19
Okay, we need to calculate all the critical points and inflection points and all that.
00:26
Okay, so for these problems you always need to take two derivatives.
00:29
So let's first take the first derivative.
00:31
So we have to use product rule.
00:33
So we first take derivative of 2x which is 2 times 2 square root square plus 3, and then we take a derivative of the square root function.
00:45
So we have 2x and then we take a derivative of the square root.
00:50
So we get square root of 2x squared plus 1 over square root of 2x squared and then times one half.
01:00
But then you have to remember you have to use chain rule on the inside portion.
01:03
So this the derivative of 2x squared plus 3 is going to be 4x.
01:10
Okay, and now let's simplify this a bit.
01:20
Okay, so now let's put it into common denominator.
01:24
So let's simplify this by putting it in a common denominator.
01:29
So let's do square root of 2x squared plus 3, and then we get 2 times 2x squared plus 3 plus 2x.
01:45
So this is going to be 2x squared, 4x squared.
01:49
Okay, so this is going to be 8x squared plus 3 over square root of 2x squared plus 3.
02:11
Okay, and then we need to also find the inflection points and all that.
02:14
So we also need to take second derivative.
02:20
So to do this, you need to use quotient rule.
02:23
So first we take derivative of the numerator, which is going to be 16x times the stuff in the denominator.
02:35
And then we take a derivative of the denominator, which is again, so we have to use the chain rule.
02:53
So we get again, derivative of denominator is going to be this.
02:56
And then we need to multiply by the numerator plus 3.
03:01
And then we divide by the denominator squared.
03:11
Okay, so the denominator squared is going to be going to be this.
03:26
Okay, and now let's try to simplify this a bit.
03:31
So again, we divide here to get 2x.
03:37
And then let's simplify the numerator by putting under common denominators.
03:46
So this is going to be 16x times 2x squared plus 3 plus 2x times 8x squared plus 3, all over square root of 2x squared plus 3.
04:14
And then we divide by 2x squared plus 3.
04:21
Okay, so this is going to be, so it's going to be 32x cubed plus 16x cubed, so it's going to be 48x cubed.
04:36
And then we get 48x plus 6x, that'll be plus 54x.
04:47
And then all this thing is going to be divided by 2x squared plus 3 to the 3 halves.
04:59
Okay, so that was a long calculation, but these are derivatives.
05:07
Okay, so now we have to check, find the critical point.
05:16
This is where f prime is equal to zero or undefined.
05:23
So this basically means when is the numerator equals zero and when is the denominator equal to zero? well, for f prime, if you look at this, the denominator is never zero, because 2x squared plus 3 is always strictly positive, never zero, right, it's always bigger than 3, or square root of 3.
05:52
So f can, f prime can never be undefined.
05:55
So the only place where it can equal zero is if you have 8x squared plus 3 equal to zero...