Question

Suppose that $\lim_{x \to 3} f(x) = \frac{3}{4}$ and $\lim_{x \to 3} g(x) = -\frac{1}{6}$. a. $\lim_{x \to 3} [f(x) + 4g(x)]$ b. $\lim_{x \to 3} [f(x)g(x)]$ c.

          Suppose that $\lim_{x \to 3} f(x) = \frac{3}{4}$ and $\lim_{x \to 3} g(x) = -\frac{1}{6}$.
a. $\lim_{x \to 3} [f(x) + 4g(x)]$
b. $\lim_{x \to 3} [f(x)g(x)]$
c.

Suppose that limx → 3 f(x) = (3)/(4) and limx → 3 g(x) = -(1)/(6).
a. limx → 3 [f(x) + 4g(x)]
b. limx → 3 [f(x)g(x)]
c.

Added by Kaitlyn S.

Calculus: Early Transcendentals

James Stewart 8th Edition

Instant Answer

Solved by Expert Vincenzo Zaccaro

09/16/2022

Step 1

We know that the limit of a product is the product of the limits, so \lim_(x->3)[3f(x)g(x)] = 3 * \lim_(x->3)[f(x)] * \lim_(x->3)[g(x)] Substitute the given limits: \lim_(x->3)[3f(x)g(x)] = 3 * (3/4) * (-1/6) Show more…

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Suppose that lim_(x->3)f(x)=(3)/(4) and lim_(x->3)g(x)=-(1)/(6). a. lim_(x->3)[3f(x)g(x)] b. lim_(x->3)[(f(x))/(f(x)-g(x))] 3 Suppose thatlim f(x) andlim gx= X->3 6 a.lim[fx)+4gx] X->3 b.lim[fxgx] X->3 C.