Question

Suppose that the functions $p$ and $q$ are defined as follows. $p(x) = -2x - 2$ $q(x) = x^2 + 2$ Find the following. $(q \circ p)(-5) = (p \circ q)(-5) = $

          Suppose that the functions $p$ and $q$ are defined as follows.
$p(x) = -2x - 2$
$q(x) = x^2 + 2$
Find the following.
$(q \circ p)(-5) = 
(p \circ q)(-5) = $

Suppose that the functions p and q are defined as follows.
p(x) = -2x - 2
q(x) = x^2 + 2
Find the following.
(q ∘ p)(-5) =
(p ∘ q)(-5) =

Added by Evan T.

Introductory and Intermediate Algebra for College Students 4th

Robert Blitzer 4th Edition

Instant Answer

Solved by Expert Rebecca Belvin

11/15/2023

Step 1

Step 1: Find (qp)(-5) To find (qp)(-5), we first need to find q(-5) and then plug that result into p(x). Show more…

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Suppose that the functions p and q are defined as follows. p(x)=-2x-2 q(x)=x^(2)+2 Find the following. (qp)(-5)= (pq)(-5)= Suppose that the functions p and q are defined as follows px=-2x-2 qx=x+2 Find the following. qp-5= X G (pq-5=