For $\hat{N}=0$, we have:
$$\frac{dN}{dt} = r\left(1-\frac{0}{K}\right)^2 0 = 0$$
For $\hat{N}=K$, we have:
$$\frac{dN}{dt} = r\left(1-\frac{K}{K}\right)^2 K = r(0)^2 K = 0$$
So, both $\hat{N}=0$ and $\hat{N}=K$ are equilibria.
(b) To determine the stability
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