Suppose that we don't have a formula for g(x) but we know that g(1) = -3 and g'(x) = \sqrt{x^2 + 8} for all x. (a) Use a linear approximation to estimate g(0.9) and g(1.1). g(0.9) \approx g(1.1) \approx
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Since we know that q(1) = -3 and q'(x) = x^2 + 8, we can find the slope of the tangent line at x = 1 by evaluating q'(1): q'(1) = (1)^2 + 8 = 1 + 8 = 9 So, the slope of the tangent line at x = 1 is 9. Now, we can use the point-slope form of a linear equation to Show more…
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