Suppose the ends of a bar are insulated, and the left half is initially (t=0) at constant temperature T while the right half is initially at temperature zero: $f(x) = \begin{cases} T & \text{for } 0 \le x \le L/2\\ 0 & \text{for } L/2 < x \le L \end{cases}$ The heat equation for this scenario has a general solution $u(x, t) = a_0 + \sum_{n=1}^{\infty} a_n \cos(\frac{n\pi x}{L})e^{-n^2 \pi^2 kt/L^2}$ Compute the coefficients $a_0$ and $a_n$ to find the particular solution of the heat equation.
Added by Brian P.
Close
Step 1
Step 1: The general solution of the heat equation for this scenario is given by xt = ao + an*cos(n*pi*x/L). Show more…
Show all steps
Your feedback will help us improve your experience
Manik Pulyani and 95 other Calculus 3 educators are ready to help you.
Ask a new question
Labs
Want to see this concept in action?
Explore this concept interactively to see how it behaves as you change inputs.
Key Concepts
Recommended Videos
If heat is generated at a constant rate throughout a bar of length $L=\pi$ with initial temperature $f(x)$ and the ends at $x=0$ and mare kept at temperature $0,$ the heat equation is $u_{1}=c^{2} u_{x x}+H$ with constant $H>0 .$ Solve this problem. Hint. Set $u=v-H x(x-\pi) /\left(2 c^{2}\right)$.
Partial Differential Equations (PDEs)
Heat Equation: Solution by Fourier Series
A thin homogenous bar having thermal diffusivity of 9 and a length of 2 cm has insulated sides and its left end maintained at zero temperature, while its right end is perfectly insulated. The bar has an initial temperature f(x) = x^2 for 0 ≤ x ≤ 2. Determine the temperature distribution u(x, t)
Sri K.
A semi-infinite bar is initially at temperature $100^{\circ}$ for $0^{\prime}<x<1$, and $0^{\circ}$ for $x>1$. Starting at $t=0$, the end $x=0$ is maintained at $0^{\circ}$ and the sides are insulated. Find the temperature in the bar at time $t$, as follows. Separate variables in the heat flow equation and get clementary solutions $e^{a^{2} \lambda^{2} t} \sin k x$ and $e^{-a^{2} k^{21}} \cos k x$. Discard the cosines since $u=0$ at $x=0$. Leok for a solution $$ u(x, t)=\int_{0}^{\infty} B(k) e^{-k^{2} a^{2 t}} \sin k x d k $$ and proceed as in Example 2. I eave your answer as an integral.
INTEGRAL TRANSFORMS
Integral transform solutions of partial differential equations
Recommended Textbooks
Calculus: Early Transcendentals
Thomas Calculus
Transcript
Watch the video solution with this free unlock.
EMAIL
PASSWORD