Question

Suppose the function $p(x)$ satisfies $p(5) = 11$, $p'(5) = 1$, and $p''(x) < 0$ for $x$ values nearby 5. (a) Find the linearization $L(x)$ of $p(x)$ at $x = 5$. (a) (b) Estimate the value of $p(5.03)$ using your linearization. (b) (c) Is your estimate an overestimate of the actual value, or an underestimate? Choose the appropriate answer. Overestimate Underestimate

          Suppose the function $p(x)$ satisfies $p(5) = 11$, $p'(5) = 1$, and $p''(x) < 0$ for $x$ values nearby 5.
(a) Find the linearization $L(x)$ of $p(x)$ at $x = 5$.
(a)
(b) Estimate the value of $p(5.03)$ using your linearization.
(b)
(c) Is your estimate an overestimate of the actual value, or an underestimate? Choose the appropriate answer.
Overestimate
Underestimate
        
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Suppose the function p(x) satisfies p(5) = 11, p'(5) = 1, and p”(x) < 0 for x values nearby 5.
(a) Find the linearization L(x) of p(x) at x = 5.
(a)
(b) Estimate the value of p(5.03) using your linearization.
(b)
(c) Is your estimate an overestimate of the actual value, or an underestimate? Choose the appropriate answer.
Overestimate
Underestimate

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Calculus: Early Transcendentals
Calculus: Early Transcendentals
James Stewart 8th Edition
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Suppose the function pxsatisfies p5=11,p5=1,and px<0 forx values nearby 5 aFind the linearization Lxof p(xat x=5. (a) (b) Estimate the value of p(5.03) using your linearization (b) (c Is your estimate an overestimate of the actual value,or an underestimate? Choose the appro- priate answer. Overestimate Underestimate
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Transcript

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00:01 Anytime you're given a problem that tells you the point, so this is basically saying that when x is 5, the y coordinate is 14.
00:14 So when i get two points of form, y minus the y coordinate equals the slope x minus the x coordinate, i already know that this would be x1 and this would be y1, which brings me to my next point that when i see f prime of 5 is equal to 5 .6.
00:33 That number is my slope.
00:37 So the linearization is basically set up this way, y minus 14 is equal to 5 .6, and then x minus the x coordinate.
00:48 I guess i should have underlined that to a 5.
00:51 But they want you to write it as f of x.
00:54 So i'm going to go ahead and distribute this 5 .6 into the problem.
01:00 Let's see, 5 .6 times 5 is 28.
01:05 But then i need to add 14 over...
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