00:01
In this problem we are given that the population p is given by p0 times e par kt and here t denotes the number of years since 2015.
00:19
We are given that in the year 2015 the population is 3 .6 million.
00:26
So we can denote that as p .0 since it is the initial population.
00:30
Considering that t is the number of years since 2015, it is clear that here t equals to 0.
00:38
So we have p0 as 3 .6 and we are given that the population in the year 2018, that is when t equals to 3 is 3 .8 million.
00:53
We are asked to find out the population in the year 2022, that is when 20 ,000 ,000 ,000, that is when t equals to 7 and also we are asked to find out the value of t when the population p equals to 4 .5 million.
01:18
So before we move on to these two problems, let us first find out the value of k using the condition p of 3 equals to 3 .8.
01:27
So substituting t as 3 we get 3 .8 equals to p .0 which is 3 .6 times e.
01:35
Are 3 times k...