Question

5. Suppose there's a vector $v = (a, 2b, -2a)$. If we know that $|v| = \sqrt{20}$ and that $v \cdot (5,2,3) = 8$, find the possible values of $a$ and $b$. [7 points]

Name: 5. Suppose there's a vector v = (a, 2b, -2a). If we know that |v| = √(20) and that v · (5,2,3) = 8, find the possible values of a and b. [7 points]
Uploaded: 2023-07-04T11:19:05-08:00
Duration: 1 min 50 s
Channel: Madhur L
Description: 5. Suppose there's a vector v = (a, 2b, -2a). If we know that |v| = √(20) and that v · (5,2,3) = 8, find the possible values of a and b. [7 points]

          5. Suppose there's a vector $v = (a, 2b, -2a)$. If we know that $|v| = \sqrt{20}$ and that $v \cdot (5,2,3) = 8$, find the possible values of $a$ and $b$. [7 points]

Added by Richard R.

Calculus: Early Transcendentals

James Stewart 8th Edition

Instant Answer

Solved by Expert Madhur L

07/04/2023

Step 1

|v| = √(a^2 + (2b)^2 + (-2a)^2) √20 = √(a^2 + 4b^2 + 4a^2) 20 = a^2 + 4b^2 + 4a^2 20 = 5a^2 + 4b^2 Show more…

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Suppose there's a vector v=(a,2b,-2a). If we know that |v|=sqrt(20) and that v*(5,2,3)=8, find the possible values of a and b. [7 points] 5.Suppose there's a vectorv=a,2b,-2a).If we know that|v|=V20 and that v5,2,3=8 find the possible values of a and b. [7 points]