00:01
Observed genotype homozygous capital a, heterozygous, and homozygous lower a.
00:08
They have the count x, y, and z.
00:16
So the question says that one calculate the total number of a allele.
00:24
So as you can see, the total capital a allele equals x individuals.
00:35
Now in this homozygous capital a, you'll have two capital a allele.
00:40
So you have two times two.
00:42
And then also you'll have heterozygous capital a lower a.
00:46
So for those individuals, you have y, the number y, but there's only one capital a, so times one.
00:56
So the total allele will be 2x plus y.
01:02
So that's the first question.
01:03
Now let's take a look at the second.
01:06
It asks you to calculate the total number of lower a allele.
01:10
Same idea.
01:14
So in homozygous lower a, you have z individual.
01:22
So these individuals, you have two lower a allele.
01:26
So z times two.
01:28
Again, in heterozygous, you'll have a one a allele.
01:33
So plus y times one.
01:37
So again, the total lower a allele is 2z plus y...