00:01
Hi, in this question, govern that limit x tends to 0, 1 by x square minus cot square x.
00:13
We need to evaluate this by using the l -hospital rule.
00:17
So, here we can write it as limit x tends to 0, 1 by x square minus cot square x can be written as cos square x divided by sin square x which is equal to limit x tends to 0 on taking lcm, then we get x square sin square x and here we get sin square x minus x square cos square x.
00:49
On applying the l -hospital rule, then we get limit x tends to 0, here we get sin 2x minus 2x cos square x plus x square sin 2x divided by here 2x sin square x plus sin 2x into x square.
01:20
Again, apply l -hospital rule, then we get limit x tends to 0, 2 cos 2x minus 2 cos square x plus 4x sin 2x plus 2 sin square x.
02:06
Again, apply l -hospital rule, then we get limit x tends to 0, here 2 sin 2x plus 12x cos 2x minus 4x square sin 2x divided by minus 4x square sin 2x plus 12x cos 2x plus 6 sin 2x...
