(1 point) Use power series to solve the initial-value problem \newline $y'' - 4xy' - 8y = 0$, $y(0) = 0$, $y'(0) = 1$. \newline Answer: $y = \sum_{n=0}^{\infty} \text{________} x^{2n} + \sum_{n=0}^{\infty} \text{________} x^{2n+1}$
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The equation 48y^2 + 0 = 0/0 + 1 can be simplified to 48y^2 = 1. Show more…
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